0.0001x^2+0.06x+-1.7=0

Solution for 0.0001x^2+0.06x+-1.7=0 equation:

0.0001x^2+0.06x+-1.7=0

We add all the numbers together, and all the variables

0.0001x^2+0.06x=0

a = 0.0001; b = 0.06; c = 0;
Δ = b2-4ac
Δ = 0.062-4·0.0001·0
Δ = 0.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.06)-\sqrt{0.0036}}{2*0.0001}=\frac{-0.06-\sqrt{0.0036}}{0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.06)+\sqrt{0.0036}}{2*0.0001}=\frac{-0.06+\sqrt{0.0036}}{0.0002}
$